Help me out on this.!!Find "ERROR" in the log file

[E.Gopi Kannan]

Hi All,

Help me out on this.!!

Example log file. say file.log

dd-mm-yyyy fsagsgsfgf ERROR:gsdagasfgsdfgaga

I want to know,

how to find the jan 1st 2011 with only ""ERROR" on the above mentioned log file.

[Ivan Krastev]

Use simple grep twice:

grep "01-01-2011" filename | grep ERROR


regards,
ivan

[E.Gopi Kannan]

thanks..!!

[Ismail Azad]

Hi,

Similar to the pharoah's way but just a little different.

cat filename | grep -e 1/1/2011 -e ERROR

That should work too. Or you can also try egrep.

Regards
Ismail Azad

[Dennis Handly]

>Ismail: Similar to the pharoah's way but just a little different.

This isn't similar, this is wrong, it does an OR, the OP wants an AND.

A better solution and without the evil cat:
grep "01-01-2011.*ERROR" filename

[Ismail Azad]

Hi,

> jan 1st 2011 with only ""ERROR".

Yup more than ERROR, important word there was "only". Was thinking in terms of "OR". Sorry bout that.

Regards
Ismail Azad

[Trond Haugen]

Previous responses are good so I just wanted to add that since the date is at teh beginning of the lines you could use:

grep "^01-01-2011" file.log | grep ERROR