How to avoid substitution with string having * characters

[SwissKnife]

Hi,

Here is my script

function myfunction {
    __TEXT=`echo "$1"`
    echo "__TEXT=${__TEXT}"
}

__AA="*** Erreur dans le passage du nombre d'arguments"
myfunction ${__AA}

My question: How to get this as an output from this script:

*** Erreur dans le passage du nombre d'arguments

Instead of this, it returns a string containing filenames !!!

 Note: I understand the WHY!!! But I do not know how to do the trick! in other words how to avoid the wildcard expansion ???

Any ideas ? thanks in advance.

Kind regards,

Den.

[Steven Schweda · Accepted solution]

> Note: I understand the WHY!!!

   Perhaps.  Perhaps not.

>  But I do not know how to do the trick! in other words how to avoid
> the wildcard expansion ???

   The usual "trick" is quotation.

> myfunction ${__AA}

      myfunction "${__AA}"

   Another method might be "set -f".  As usual, many things are
possible.

[Dennis Handly]

> __TEXT=`echo "$1"`

What is the purpose of this?  Why not: __TEXT="$1"

[Steven Schweda]

> > __TEXT=`echo "$1"`
> What is the purpose of this?  Why not: __TEXT="$1"

   Or even: __TEXT=$1

pro3$ x='aa bb cc'
pro3$ y=$x
pro3$ echo $y
aa bb cc

   In more complicated expressions, more quotation may be more helpful.


   For future reference:

> Note: I understand the WHY!!!

   A statement like this conveys no useful information.  What, exactly,
do you know (or believe that you know)?  Are you saying that that you
understand how the shell "globs" a "*"?  Or that you understand how
quotation works?  Or what?

   In many cases, the act of forming a question well will itself lead
you to the answer, which can save everyone some work.