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Re: Parameter substitution in shell: does ${##} work ?

 
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Arturo Galbiati
Esteemed Contributor

‎10-24-2006 08:03 PM

‎10-24-2006 08:03 PM

Re: Parameter substitution in shell: does ${##} work ?

Hi,

/> X=00000034
/> echo $X
00000034
/> X=$(( X+0 ))
/> echo $X

the rtick is to add 0 to force the varibale to be an integer. In this way the leading zeros will be removed.

HTH,
Art
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CAS_2
Valued Contributor

‎10-24-2006 08:25 PM

‎10-24-2006 08:25 PM

Re: Parameter substitution in shell: does ${##} work ?

Thanks, Peter
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