counting number of rows in awk

[lawrenzo_1]

hello all,

I am now attempting to add up the number of rows in the file that have more than 42 characters and output the total number of rows:

nawk '{len = length($0); if (len > 42) ??

I have attempted some syntax that I use to count total rows in the file however how can I just count the rows > 42?

Thanks

Chris.

[Sandman! · Accepted solution]

# nawk '{if(length($0)>42) cnt++}END{print cnt}' file

[James R. Ferguson]

Hi Chris:

# awk 'END{print i};{len=length($0);if (len > 42) {i++}}'

Regards!

...JRF...

[Oviwan]

Hey

use sed:
sed -n '/^.\{43\}/p' file1 | wc -l

Regards

[James R. Ferguson]

Hi (again) Chris:

You can even write this more tersely, thusly:

# awk 'length>42 {i++};END{print i}' file

Regards!

...JRF...

[lawrenzo_1]

nice one

thanks again all!