handling arrays in "awk"

[Stuart Abramson]

I wrote this little script to "flatten out" an lvdisplay of all of the LVs on my system.

I am collecting all of the PVs in an LV in an array PV[], but I don't know how to print them all out on one line.

Can one of you "awk wizards" help me, please?

for VGROUP in $VOLGRPS
do
LVOLS=$( vgdisplay -v $VGROUP | grep "LV Name" | sort | awk '{print $3}' )
set $LVOLS
NLVS=$#
print $VGROUP $NLVS
for LV in $LVOLS
do
LVNAME=$( basename $LV )
lvdisplay -v $LV | awk -v LVName=$LVNAME '
/Mirror/ {MIRS = $3}
/LV Size/ {SIZE = $4}
/Current LE/ {LES = $3}
/Allocated PE/ {PES = $3}
/Stripes/ {STRIPES = $2}
/ \/dev\/dsk/ {PV[CNT] = substr($1,10);
CNT = CNT + 1}
END {print LVName, MIRS, SIZE, LES, \
PES, STRIPES, CNT, PV[$@]} ........<===
'
done

[James R. Ferguson · Accepted solution]

Hi Stuart:

You need to walk through each array element:

...
for (i=1;i<=CNT;i++) {printf "%s ",PV[i]};print "\n"}
...

Use the 'printf' command in lieu of 'print' to print without injecting a newline.

Regards!

...JRF...

[curt larson_1]

something like this should do:

END {
printf("%s %s %s %s %s %s %s", LVName, MIRS, SIZE, LES, PES, STRIPES, CNT);
#use printf so there is no newline
for ( i in PV ) printf(" %s", PV[i]);
#although this isn't garanteed to be in order
# to be sure they are in order:
#for (i=0;i++;i#and finally a new line
printf("\n");
}

[Sandman!]

Replace the instance of PV[$@] with the following:

END {print ; for (s in PV) printf("%s ", PV[s]); print "\n"}

regards!

[Muthukumar_5]

Use this script as,

for VGROUP in $VOLGRPS
do
LVOLS=$( vgdisplay -v $VGROUP | grep "LV Name" | sort | awk '{print $3}' )
set $LVOLS
NLVS=$#
print "VGROUP\t No. LVs"
print "$VGROUP $NLVS\n"
printf LVName" "MIRS" "SIZE" "LES" "PES" "STRIPES" "PVNAME"\n"

for LV in $LVOLS
do
LVNAME=$(basename $LV )
lvdisplay -v $LV | awk -v LVName=$LVNAME '
/Mirror/ {MIRS = $3}
/LV Size/ {SIZE = $4}
/Current LE/ {LES = $3}
/Allocated PE/ {PES = $3}
/Stripes/ {STRIPES = $2}
/^ +\/dev\/dsk/ {PV[CNT] = substr($1,10);CNT = CNT + 1}
END {printf ("%-6s %-4d %-4d %-3d %-3d %-8s",LVName,MIRS,SIZE,LES,PES,STRIPES); for (s in PV) { printf PV[s]; }printf "\n";}'

done
done

hth.

[Stuart Abramson]

These all look good. I'll try them today. thanks.