replace data in a stanza

[lawrenzo_1]

Hi all,

I want to search a file for a sting then change the last field in the last row of that stanza if it doesn't match a string:

this is how the stanza's look:


usw:
shells = /bin/sh,/bin/bsh,/bin/csh,/bin/ksh
maxlogins = 3000
logintimeout = 60
auth_type = STD_AUTH

next stanza: shells =
maxlogins =
logintimeout =
auth_type = STD_AUTH

in this example when the string usw is matched, check the auth_type and replace STD_AUTH with PAM_AUTH.

I have an idea how to do this by removing the stanza completely and then appending the usw stanza to the bottom of the file and changing STD_AUTH with PAM_AUTH.

I am sure there is a more logical way of doing this?

Thanks

Chris.

[Steven E. Protter · Accepted solution]

Shalom Chris,

I think sed may be an answer.

websitename=bsg21.org
sed s/hpuxconsulting.com/$websitename/g hpuxconsulting.com.virt.conf > $websitename.virt.conf

What this sed sequence does is take a template file hpuxconsulting.com.virt.conf and make a changed copy in this case bsg21.org, the last one I used it on.

It efficiently does a replace and creates a new file with everywhere it sad hpuxconsulting.com now saying bsg21.org

SEP

[James R. Ferguson]

Hi Chris:

Treat each stanza as its own record:

# perl -pe '$/="";if (/^usw/) {s/STD_AUTH/PAM_AUTH/}' file

...of course to update in-place:

# perl -pi.old -e '$/="";if (/^usw/) {s/STD_AUTH/PAM_AUTH/}' file

Regards!

...JRF...

[James R. Ferguson]

Hi (again) Chris:

Oh, if you prefer 'awk' this works analogously ...

# awk 'BEGIN{RS=""};/^usw/ {sub("STD_AUTH","PAM_AUTH")};{print $0,"\n"}' file

Regards!

...JRF...

[lawrenzo_1]

Thanks for you help again .....

I have used the awk version however the perl and sed would have done the trick.

Chris

:-)