convert day of year to date

[JKrucus]

I can get the day of year from f$cvtime, but I need the reverse. Is there a way to input the 82 and get the 23-mar-2006 date returned?

CAT>> WRITE SYS$OUTPUT F$CVTIME(,,"DAYOFYEAR")
82
CAT>>sho time
23-MAR-2006 11:39:56

[Hein van den Heuvel · Accepted solution]

$ write sys$output f$cvtime("1-jan +82-")

Hein.

[Hein van den Heuvel]

ooops... off by 1

but you get the drift....

The - behind the 82 is critical to change is from 'hours' to 'days'


Hein

[JKrucus]

Excellent