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Operating System - Tru64 Unix
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DRIVER OWNER and disk and hwmgr

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Adam Garsha
Valued Contributor

DRIVER OWNER and disk and hwmgr

What does "Driver Owner" refer to in 'hwmgr -show scsi'. Just did a VCS upgrade test on our EVA array and that parameter changed for my test disk. Just curious what it means.

SCSI DEVICE DEVICE DRIVER NUM DEVICE FIRST
HWID: DEVICEID HOSTNAME TYPE SUBTYPE OWNER PATH FILE VALID PATH
-------------------------------------------------------------------------
178: 45 jupiter disk none 2 4 dsk17 [6/7/1]

WWID:01000010:6005-08b4-0001-42f7-0002-3000-0008-0000


BUS TARGET LUN PATH STATE
---------------------------------
6 7 1 valid
6 8 1 valid
7 7 1 valid
7 8 1 valid
4 REPLIES
Stiwi Wondrusch
Trusted Contributor

Re: DRIVER OWNER and disk and hwmgr

Hi Adam

See:
http://h30097.www3.hp.com/docs/base_doc/DOCUMENTATION/V51B_HTML/ARSFCATE/TITLE.HTM

chapter: "3.4.10 Deleting a SCSI Device"

rgds Stiwi
Adam Garsha
Valued Contributor

Re: DRIVER OWNER and disk and hwmgr

Yes, but that doesn't tell me what it means for a disk device.
Stiwi Wondrusch
Trusted Contributor
Solution

Re: DRIVER OWNER and disk and hwmgr

From:
http://h30097.www3.hp.com/docs/base_doc/DOCUMENTATION/V51B_HTML/ARSFC
ATE/TITLE.HTM

chapter: "3.4.10 Deleting a SCSI Device"

"In this example, the DRIVER OWNER field is not zero for component ID 23, indicating that the device is currently open by a driver. Any number other than zero in the DRIVER OWNER field means that a driver has opened the component for use. Therefore, you cannot delete SCSI component 23 because it is currently in use."

rgds Stiwi
Adam Garsha
Valued Contributor

Re: DRIVER OWNER and disk and hwmgr

I gave you the points because my question wasn't clear.

I guess I want to know what "0" means for a disk device vs. "2" when in both cases the disk device is "open" and filesystem are mounted.

It doesn't make sense to me, I guess that one device (one with very little I/O) would have a solid "2" in the field, while a super busy one has a "0".

The only difference between the two disks is that one EVA is presenting active/active-ly and the other is presenting active/passive-ly; the "0" is associated with the active/passive array's disk and the "2" is associated with the active/actve arrays disk.