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тАО02-19-2010 10:12 AM
тАО02-19-2010 10:12 AM
i need to get some paths.
This paths can contain the word:
Archive
ARCHIVE
archive
archivE
aRcChIvE
so, if i run:
find / -mtime +14 -exec ls -l {} \; | awk '{ print $3" "$4" "$6" "$7" "$8" "$NF }' | grep Archive
i only will get paths with a directory name called "Archive" so, how can i do in order to get above word indicated,i need to get them in only one instruction.
i mean,, i need to run command where i say "bring me paths which contain the word Archive never mind if they are uppercase or lowercase"
thansk in advance.
Solved! Go to Solution.
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тАО02-19-2010 10:31 AM
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тАО02-19-2010 10:53 AM
тАО02-19-2010 10:53 AM
Re: Find a word in a directory, never mind uppercase or lowercase
find / -mtime +14 -name "[Aa][Rr][Cc][Hh][Ii][Vv][Ee]" -exec ls -ld {} + |
awk '{ print $3, $4, $6, $7, $8, $NF }'
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тАО02-19-2010 11:06 AM
тАО02-19-2010 11:06 AM
Re: Find a word in a directory, never mind uppercase or lowercase
If you want *performance* you could use Perl's 'find' module:
# perl -MFile::Find -le '@dir=@ARGV?@ARGV:(".");find(sub{print $File::Find::name if m{archive}i && -M $_ > 14},@dir)' /path
You can change to the current directory and run this without any argument to examine it, or you can specify one or more '/path' arguments as above.
Regards!
...JRF...
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тАО02-19-2010 02:32 PM
тАО02-19-2010 02:32 PM