Ksh parameter not set error

[Anand_30]

I am trying to extract some file in the following format.

month date time file

I am using the following command:

ls -l|grep file|print{$6,$7,$8,"/t"$9}

But I am getting the following error:
ksh:parameter not set

Can anyone please tell me how to get rid of this problem.

Thanks,
-Anand

[Steven E. Protter]

Post the script.

It looks like you don't have the shell defined properly.


#!/usr/bin/ksh


For example.

SEP

[Mark Grant · Accepted solution]

I think it thinks "print" is parameter.

Try

ls -l | grep file | awk '{ print $6,$7,$8,"\t",$9 }'

[Jean-Luc Oudart]

try
ls -l|grep file|awk '{printf("%s %s %s\t%s\n",$6,$7,$8,$9);}'

I suppose "file" has different value depending on your query

Rgds,
Jean-Luc

[Anand_30]

Thanks

Both the commands worked fine.

-Anand.

[setubabu s]

HI Anand,

use the awk command.

ls -l |grep file |awk '{print $6,$7}'

[Johnson Punniyalingam]

Hi setubabu s,

is there any point in reply to thread which opend 7 year older ...:(

Sep 30, 2003 12:59:41 GMT N/A: Question Author

[Horia Chirculescu]

>is there any point in reply to thread which opend 7 year older

Maybe there is a time loop out there...

See Stargate SG1/Atlantis episodes. (http://stargate.mgm.com/)

Horia.