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03-23-2011 10:01 PM
03-23-2011 10:01 PM
The problem is this: Documentation says that load average is the number of all active processes. But in the output it seems that it's divided by the number of processors. Is this standard for HP-UX?
My second question is: if it is really divided by #processors, what LOAD means for the particular processors - does each processor have its own queue? I doubt it. How it is calculated? Does anyone have an explanation for this?
Load averages: 1.75, 1.12, 1.00
472 processes: 412 sleeping, 59 running, 1 zombie
Cpu states:
CPU LOAD USER NICE SYS IDLE BLOCK SWAIT INTR SSYS
0 1.69 62.0% 5.0% 30.5% 2.6% 0.0% 0.0% 0.0% 0.0%
1 1.72 47.0% 20.7% 29.1% 3.2% 0.0% 0.0% 0.0% 0.0%
2 1.78 61.0% 9.8% 27.7% 1.6% 0.0% 0.0% 0.0% 0.0%
3 1.80 65.9% 8.0% 23.9% 2.2% 0.0% 0.0% 0.0% 0.0%
--- ---- ----- ----- ----- ----- ----- ----- ----- -----
avg 1.75 59.1% 10.8% 27.7% 2.4% 0.0% 0.0% 0.0% 0.0%
Solved! Go to Solution.
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03-24-2011 04:24 AM
03-24-2011 04:24 AM
Re: LOAD AVERAGE on HP-UX SMP
>Documentation says that load average is the >number of all active processes.
This is not true. I doubt you have found somewhere in the docs (both HP-UX or for any UNIX) such an affirmation.
The load average is the average number of processes in the queue waiting
for CPU time, over the last 1, 5, and 15 minutes.
Best regards,
Horia.
Horia.
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03-24-2011 07:04 AM
03-24-2011 07:04 AM
Re: LOAD AVERAGE on HP-UX SMP
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03-24-2011 07:28 AM
03-24-2011 07:28 AM
Solutionhttp://docs.hp.com/en/5965-4643/ch01s13.html
Implicit to some extent by the fact that you can create a pset with a single processor.
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03-24-2011 10:06 PM
03-24-2011 10:06 PM
Re: LOAD AVERAGE on HP-UX SMP
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04-16-2012 05:06 PM
04-16-2012 05:06 PM
Re: LOAD AVERAGE on HP-UX SMP
Hi guys, i´m still confused about load averages. Maybe is because i´m trying to make a relation with load averages of command "top" and enqueuing runing processes from "vmstat" column (r).
He is the think, we have a server with 6 cpu´s, and with top command i can see that "load averages" is always between 2 to 4... and at the same time if a prompt for example: "vmstat 1 100", i see that column (r) is with 20 to 30 processes in waiting, cpu with 85% to 98% usage, and idle 0 to 10, ok? This is the fact!
So, what I would like to know is, if there is a relation between these commands and information?
And how can I surely see the enqueue processes?
Could someone help please?
Thanks!