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тАО01-19-2006 06:38 AM
тАО01-19-2006 06:38 AM
Solved! Go to Solution.
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тАО01-19-2006 06:42 AM
тАО01-19-2006 06:42 AM
Re: More Time
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тАО01-19-2006 06:43 AM
тАО01-19-2006 06:43 AM
Re: More Time
You need to look at a combination of the touch and find commands. Use touch to create a file with a time stamp of 5 minutes prior. Then use find to detect and remove any files older than your reference file.
touch -t [[CC]YY]MMDDhhmm[.SS] ref_file
find /start_dir -type f ! -newer ref_file -exec rm {} \;
-or-
find /start_dir -type f ! -newer ref_file | xargs rm
Pete
Pete
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тАО01-19-2006 06:44 AM
тАО01-19-2006 06:44 AM
Re: More Time
You can use command
touch -t time file_stamp
time can be set up somehow as now -5 minutes
After you run
find dirname -newer file_stamp -exec rm {} \;
HTH
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тАО01-19-2006 07:12 AM
тАО01-19-2006 07:12 AM
SolutionFirst compute a timestamp that is 5-minutes less than the current time:
Use the following perl script called "/tmp/time":
#!/usr/bin/perl
$t=((time)-300);
($mon,$day,$hr,$min)=(localtime($t))[4,3,2,1];
$mon++;
printf("%02d%02d%02d%02d\n",$mon,$day,$hr,$min)
In your cron task do:
# TS=`/tmp/time`
# touch -amt ${TS} /tmp/myref
# find /path -xdev -type f ! -newer /tmp/myref | xargs rm
# find /path -xdev -type d -newer /tmp/myref | xargs rmdir
exit 0
This does a pass for files first, and then secondarily for empty directories. Since deletion of the files in a subdirectory will update the directory's timestampe ('mtime') I chose the positive form of '-newer' whereas the negated '-newer' argument was applied to the files.
Regards!
...JRF...
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тАО01-19-2006 08:42 PM
тАО01-19-2006 08:42 PM
Re: More Time
I use this command to remove teh core file:
It founds the core file in the current modified from 24 hours ago to now
find . -name "core" -mtime -1 -type f -exec rm {} \;
I scheduled it in crontab to run every 5 minutes and teh result is that I remove teh core file every 5 minutes.
HTH,
Art
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тАО01-19-2006 09:33 PM
тАО01-19-2006 09:33 PM
Re: More Time
Your cron job (which runs every 5 minutes) should look for a reference file in a known location.
If the file is absent, then create it (its timestamp will be set to now) do nething else this time.
If the file is present, then it was created by your cron job 5 minutes ago, so any file older than it can be removed. Then touch your reference file (its timestamp will be set to now) so that the next time the cron job runs it will be 5 minutes old.
The advtange of doing it this way is you can change how old the files need to be before deleting them by changing the cron job frequency rather than having to edit the script each time.
Just my ├В┬г0.02 worth.
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тАО01-20-2006 12:55 AM
тАО01-20-2006 12:55 AM
Re: More Time
# find /path -xdev -type f ! -newer /tmp/myref | xargs rm
# find /path -xdev -type d -newer /tmp/myref | xargs rmdir
James, just looking at it, the above seems to delete all files that are younger than the reference file /tmp/myref rather than older.
Am I reading this wrong? What can I put on the end to replace the xargs rm and xargs rmdir that will show me which files are fixing to be deleted before I actually try and run a test of this.
So far, the script looks like this ...
rm /tmp/myref
START=${HOME}
echo ${START}
TARGET=${HOME}/targetdir
echo ${TARGET}
cd ${TARGET}
#####
# Run temp_time to get the date time less 5 minutes
#####
TS=`${PS_HOME}/temp_time`
#####
# Touch to create a reference file in tmp directory
#####
touch -amt ${TS} /tmp/myref
#####
# find all files and directories in the target directory that are older
# than the reference file.
#####
find ${TARGET} -xdev -type f ! -newer /tmp/myref | xargs rm
find ${TARGET} -xdev -type d -newer /tmp/myref | xargs rmdir
#####
# Exit script
#####
cd ${START}
exit 0
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тАО01-20-2006 12:57 AM
тАО01-20-2006 12:57 AM
Re: More Time
Pete
Pete
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тАО01-20-2006 12:59 AM
тАО01-20-2006 12:59 AM