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Proc table is full

 
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Waqar Razi
Regular Advisor

Proc table is full

I am having this message "PROC table in full" in HPUX server.

Is there any way to solve this problem without rebooting the server.
7 REPLIES
Michal Kapalka (mikap)
Honored Contributor

Re: Proc table is full

Hi,

check this link :

http://forums11.itrc.hp.com/service/forums/questionanswer.do?threadId=721538

increase kernel parameters.

mikap
Pete Randall
Outstanding Contributor
Solution

Re: Proc table is full

No, the proc table is part of the kernel. Increasing it's size requires changing the value of nproc, rebuilding the kernel and rebooting the server in order to load the new kernel.


Pete

Pete
Steven E. Protter
Exalted Contributor

Re: Proc table is full

Shalom,

Increase nproc

Also check maxuprc

Thats the maximum amount of processes for an individual user. I've seen Oracle push the default (75) on some systems.

SEP
Steven E Protter
Owner of ISN Corporation
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http://hpuxconsulting.com
Sponsor: http://hpux.ws
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Founder http://newdatacloud.com
Bill Hassell
Honored Contributor

Re: Proc table is full

> Is there any way to solve this problem without rebooting the server.

Yes. Stop running so many processes. Have users log out and wait their turn. You might have a runaway process that is constantly starting new processes but this assumes that you have looked at your process count (sar -v 1 1) before you had a problem. If NPROC has always been too small, then you will have to keep users off the system until you can triple the NPROC value, build the new kernel and reboot.


Bill Hassell, sysadmin
Suraj K Sankari
Honored Contributor

Re: Proc table is full

Hi,

Solve the problem change the nproc value

Suraj
avizen9
Esteemed Contributor

Re: Proc table is full

you should change nproc value,

please refer below doc kernal tuning guide, and see nproc for help,
http://docs.hp.com/en/1219/tuningwp.html

Re: Proc table is full

>Is there any way to solve this problem without rebooting the server.

On 11.23, nproc is dynamic so just use kctune(1m) to increase it.