Sed display only last 8 character of filename.

[Ben Alcock]

I would like to display the last 8 characters of the filenames for filenames of different lengths.

I can delete the last 8 characters with sed but dont know how to only show the last 8 characters.

The filenames are something like;

afxH340800340000
afxH30800340021
afxR3080034002122

I have used;

echo $file | sed -e 's/........$//g'

Any help is greatly apprecaited.

Cheers

Ben

[Ivan Ferreira]

You could use:

awk '{ print substr($0,length($0)-8,length($0)) }' file

[Matti_Kurkela]

Here's how to solve it with sed:

echo $file | sed -e 's/^.*\(........\)$/\1/g'

MK

[Ben Alcock]

Thanks guys, I ended up solving this with

echo "afxH340800340000" | sed -e 's/.*\(.\{8\}\)$/\1/'