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grep help

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George Chechakunnil
Frequent Advisor

grep help

Hi

i have a file with series of entries with 4 lines each in a group

How can i search for a pattern and print all the 4 lines

checking bbb on xny
The Password Aging policy is==> DISABLED
The Account Life time ==> NEVER EXPIRES
Number of unsuccesful logins Allowed ==> INFINITE


checking qwe on qwqw
The Password Aging policy is==> DISABLED
The Account Life time ==> NEVER EXPIRES
Number of unsuccesful logins Allowed ==> INFINITE

checking eqw on inqw
The Password Aging policy is==> DISABLED
The Account Life time ==> NEVER EXPIRES
Number of unsuccesful logins Allowed ==> DEFAULT

checking eqw on inqw
The Password Aging policy is==> DISABLED
The Account Life time ==> NEVER EXPIRES
Number of unsuccesful logins Allowed ==> INFINITE


for the one that has DEFAULT i want to print out the 4 lines above that

checking eqw on inqw
The Password Aging policy is==> DISABLED
The Account Life time ==> NEVER EXPIRES
Number of unsuccesful logins Allowed ==> DEFAULT

how can i do this?

Thanks in advance




I am like a small boy picking up pebbles in god's vast shore of knowledge --- Sir Issac Newton
10 REPLIES
Pete Randall
Outstanding Contributor

Re: grep help

George,

From "Handy One-Liners for Sed" (attached):

# print paragraph if it contains AAA (blank lines separate paragraphs)
# HHsed v1.5 must insert a 'G;' after 'x;' in the next 3 scripts below
sed -e '/./{H;$!d;}' -e 'x;/AAA/!d;'


Pete

Pete
James R. Ferguson
Acclaimed Contributor

Re: grep help

Hi :

You could do :

# perl -e '$/="";while (<>) {print if /DEFAULT/}' file

or:

# awk 'BEGIN{RS=""};/DEFAULT/ {print}' file

Regards!

...JRF...
Dennis Handly
Acclaimed Contributor

Re: grep help

>JRF: # perl -e '$/="";while (<>) {print if /DEFAULT/}' file
># awk 'BEGIN{RS=""};/DEFAULT/ {print}' file

I'm not sure how these print out the previous 3 lines and the line with DEFAULT?
I'm assuming the files have zillions of lines and possibly a few of these 4 line blocks.

Of course here GNU grep would work with -B3.
James R. Ferguson
Acclaimed Contributor

Re: grep help

Hi:

> Dennis: I'm not sure how these print out the previous 3 lines and the line with DEFAULT?

They do _IF_ as the post suggests that the input file is composed of paragraphs with a blank line as the stanza seperator.

Of course, that's my assumption and it would be obviously better if the OP had _attached_ the input.

...JRF...
George Chechakunnil
Frequent Advisor

Re: grep help

Thanks for the Help but i am not getting the output as i want

The attached is the input file.. they in paragraphs each of 4 lines each.

Now i want the output to have all the paragraphs that have the word DEFAULT in it.

Desired output

checking kcrpw on inuap700
The Password Aging policy is ==> DEFAULT
The Account Life time ==> NEVER EXPIRES
Number of unsuccesful logins Allowed ==>DEFAULT(6)


checking kcrpw on inuap705
The Password Aging policy is ==> DEFAULT
The Account Life time ==> NEVER EXPIRES
Number of unsuccesful logins Allowed ==>DEFAULT(6)

checking glprd on inuap706
The Password Aging policy is==> DISABLED
The Account Life time ==> NEVER EXPIRES
Number of unsuccesful logins Allowed ==>DEFAULT(6)


etc etc


Thanks a lot in advance
I am like a small boy picking up pebbles in god's vast shore of knowledge --- Sir Issac Newton
Dennis Handly
Acclaimed Contributor
Solution

Re: grep help

>The attached is the input file. they are in paragraphs each of 4 lines each.

Your input file doesn't have empty lines as separators, they have one space.

You will have to change what was given to:
sed -e '/...*/{H;$!d;}' -e 'x;/DEFAULT/!d' file

sed -e 's/^ *$//' file | awk '
BEGIN { RS=""}
/DEFAULT/ {print}'

Or explicit programming for what's there:
awk '
/^checking / {
getline l2; getline l3; getline l4
if (l2 ~ /DEFAULT/ || l3 ~ /DEFAULT/ || l4 ~ /DEFAULT/) {
print $0; print l2; print l3; print l4
}
}' file

>JRF: input file is composed of paragraphs with a blank line as the separator.

I found the standard where it describes RS="". It sure isn't on the man page.
George Chechakunnil
Frequent Advisor

Re: grep help

Terrific

Thanks to all..

I am like a small boy picking up pebbles in god's vast shore of knowledge --- Sir Issac Newton
Tingli
Esteemed Contributor

Re: grep help

Although this post is too late, but I cannot help it.
sed -n -e ''/DEFAULT/'!{H;x;s/^.*\n\(.*\n.*\n.*\)$/\1/;x;}' -e ''/DEFAULT/'{H;x;p;}' File_Name
Hein van den Heuvel
Honored Contributor

Re: grep help

Also too late, also redundant, but maybe helpful to someone some day as it is more 'open ended'.

$ perl -ne 'if (/\S/) { push @p,$_ } else {print @p if grep /DEFAULT/,@p; @p=("\n")}' x.txt


This looks for (arbitrary) paragraph markers, here a line with only whitespace.

IF a line with non=whitespace is found, it is pushed onto a paragraph array p.
ELSE the array p that was build up is grepped for a target (DEFAULT) and the whole array printed on match. The array is then reset to a single new-line for the next go around.

btw... if there might not be a final paragraph marker, then you may want to turn it arouns some to catch a hit on the last paragraph:

perl -ne '{ push @p,$_ } if (/^\s*$/ or eof) {print @p if grep /DEFAULT/,@p; @p=()}' a.txt

fwiw,
Hein.
James R. Ferguson
Acclaimed Contributor

Re: grep help

Hi (again):

I just noticed this thread bubble to the top again.

> Dennis: Your input file doesn't have empty lines as separators, they have one space.

Ahh...now I see the reason for the confusion and the failure of my original suggestion to yield the output that George wanted [read on].

> Dennis: I found the standard where it describes RS="". It sure isn't on the man page.

Ahh, yes, again!

Based on the original post (before the attachment of text), it appeared to me that blank lines consisted solely of newline characters and these separated the stanzas or paragraphs. My suggest was based upon that assumption.

In Perl, when that is the case, if you set the record separator ('$/') to a null string, one or more blank lines constitute a record terminator. Unfortunately, a "blanK line can consist only of a newline character without hidden spaces or tabs. Perhaps more unfortunately, Perl doesn't allow a pattern in place of a simple string for the record separator.

In the GNU 'awk' documentation, it is noted that an empty string for the value of 'RS' signals that records are separated by one or more blank lines. Dennis is correct; this _isn't_ described on the HP-UX manpages. It works, though.

Of my two original code snippets, I should have slightly modified the 'awk' variation to give back at least one blank line. The Perl snippet could be better written for the way the Forum blends whitespace too:

# perl -e '$/=qq();while (<>) {print if /DEFAULT/}' file

or:

# awk 'BEGIN{RS=""};/DEFAULT/ {print $0, "\n"}' file

Finally, to filter your raw data so that it is suitable to being piped to either of the above snippets, you could do (for example):

# perl -pe 's/^\s+$/\n/' file | perl -e 'BEGIN{$/=qq()};while (<>) {print if /DEFAULT/}'

Regards!

...JRF...