run script error

[heaman1]

if [[ ! $((`date +%d`)) -eq 8 ]]
then
echo test1
else
echo test2
fi


I have a script as above , when I run it , it pop the error below.

08: value too great for base (error token is "08")


Today is 8th , If I change the date to other date , the problem will not happen , can advise what is wrong ? thx

[Venkatesh BL · Accepted solution]

# if [[ ! $((`date +%d`)) -eq 8 ]]
> then
> echo test1
> else
> echo test2
> fi
test2 <<<<

Works for me!

Can you give the output of 'date' command on your machine? What is the OS version?

[heaman1]

RH Linux

$date
Thu Jan 8 07:00:22 GMT 2009

[Dennis Handly]

You have been hosed by the Posix Standard where they want to use the junky C convention that 0n is an octal number. You'll either have to use ksh or a string compare:
if [ $(date +%d) != "08" ]; then

Or remove that $(( )), which screams C!
if [ $(date +%d) -ne 8 ]; then

This will duplicate your error:
echo $(( 08 ))

[heaman1]

thx reply ,

I tried below , it seems works,

if [[ $(date +%d) != "07" ]]


but may I ask why this problem only happens when today is 8th or 9th ? thx

[Steven Schweda]

> [...] why this problem only happens when
> today is 8th or 9th ?

Because 0-7 are valid octal digits, while 8
and 9 are not? And days not beginning with
"0" are not interpreted as octal numbers?