Find Command

[scott5555]

I am using the below find command in my code and i am redirecting the output to a file findout in the /tmp folder. I am concerned about the disk space of the tmp folder. It's now having 459 MB free space. I want to check if the output of find command is below 50 MB redirect the output to the findout file in /tmp folder otherwise throw a message "find out exceeded 50 MB limit" How can i do it?
find . -name "R*.ulog.gz" | xargs zgrep -i "SEARCHCONTENT" | cut -f 1 -d ' ' >/tmp/findout

[Dennis Handly]

>otherwise throw a message "find out exceeded 50 MB limit" How can i do it?

There are no good ways to do this without doing the find twice. Or read it all in memory and stop if too large.
Or put the file elsewhere and then move it to /tmp if < 50 Mb.

[Masud Parvez]

You can do it by script

this script might work

nohup find . -name "R*.ulog.gz" | xargs zgrep -i "SEARCHCONTENT" | cut -f 1 -d ' ' >/tmp/findout &
while TRUE=ITRC;
do
SPACE=`du -sk /tmp/findout | awk '{print $1}'`
if [ "51200" -le "$SPACE" ]
then
echo "PROCESS ID $!"
echo "OVER SIZE STOPPING FIND PROCESS"
exit 0
else
echo "SIZE UNDER 50 MB"
fi
sleep 1
done

[Deepak Kr]

Single find command will not suffice this requirement.

Dennis is right you have to use find twice.