hex to decimal

[Chris Frangandonis]

All,

I have 4 col's, the 4th col is in hex value (8e00). I would like to awk -printf $1-$4, with the 4th col being converted to dec.

Appreciate the assistance, Chris

[Peter Kloetgen]

Hi,

you could use the typeset- command to convert the format before giving it to awk- script:

typeset -i# var=value

# is for desired system:

typeset -i2 var=8
echo $var
2#100 --> binary system output

echo $var | cut -c3-
100 --> voila, the output you want, system is changable of course


Allways stay on the bright side of life!

Peter

[Carlos Fernandez Riera · Accepted solution]

using ksh:


let -i h=16#1
while read a b c d
do
let h=16#$d
echo $a $b $c $d $h
done

[Chris Frangandonis]

Hi Carlos,

Thanks, but when in hex (8e00), it should read as 008e, then 0x008e to be converted into dec.

Chris

[Carlos Fernandez Riera]

search 'hexadecimal' on the forum too.

[harry d brown jr]

Chris,

Byte swapped eh?

try this:

echo 1234 2345 3456 8e00 | awk '
{
hexstr="0123456789abcdef"
newnum=tolower(substr($4,3,2) substr($4,1,2))
slen = length(newnum)
decnum = 0
for (i=1; i < slen+1;i++)
{
tpos = index(hexstr,substr(newnum,i,1)) - 1
decnum = decnum + ( (16 ** (slen -i)) * tpos)
}
printf("%s is %d\n",newnum,decnum)
} '



live free or die
harry