Rename file

[la_cool]

I have a silly question,
I need to rename 10000 files all in 1 shot,
I know "mv command" doesn't support wild card characters

For eg: Files
payee1.dat to payee_plan1.dat
payee2.dat to payee_plan2.dat
payee3.dat to payee_plan3.dat
.....

[Dave Hutton]

Probably a few different ways of doing this but you can:
filenames=`ls -1 | grep payee`
for filenames in $filenames
do
mv $filenames $filenames.old
done

Dave

[Todd McDaniel_1]

Here is something I did once...

Using cut...

for name in `ls *.php3`
do
name1=` echo $name| cut -f 1 -d . `
mv $name1.php3 $name1.php
done


Cut the first part and last part...

[Todd McDaniel_1]

for name in `ls -la *.dat`
do
name1='echo name|cut 1-5`
name2='echo name|cut 6-10`
mv $name $name1_plan$name2
done

Or make a file and use:

for name in `cat file.in`

[curt larson_1]

ls payee*.dat |
while read file
do
file=${file%.dat}
file=${file#payee}
mv payee${file}.dat payee_plan${file}.dat
done

[Jose Mosquera]

Hi,

SUFIX=payee_plan
FILES=`ls`
for FILE in $FILES
do
DOT_POSSITION=`echo $FILE|awk '{ print index( $1, ".")}'`
POSSITION=`expr $DOT_POSSITION - 1`
SUFIX=`echo $FILE|cut -c$POSSITION-`
NEW_NAME=${PREFIX}${SUFIX}
mv $FILE $NEW_NAME
done

Rgds.

[Hein van den Heuvel]

I just yesterday had to do something very similar:

I used this simple (I'm sure I can figure out a shorter 'smarter' solution :-) perl one-liner to do my job. (tested):

ls .*560* | perl -ne 'chop; $o=$_; $_ =~ s/560/585/; rename $o,$_;'


For you that could be (untested):

ls payee*.dat | perl -ne 'chop; $o=$_; $_ =~ s/payee/payee_plan/; rename $o,$_;'


Now, before acting on the files I always make a dry-run with print or echo statements.
So try this first:

ls payee*.dat | perl -ne 'chop; $o=$_; $_ =~ s/payee/payee_plan/; print "rename $o,$_\n";'

hth,

Hein.

[harry d brown jr]

perl -e 'open(files2move,"find . -name \"payee*\.dat\" |");while ()
{s/\.\/([a-zA-Z]{1,})([0-9]{1,})\.dat/\/usr\/bin\/mv \1\2.dat \1_plan\2.dat/;print $_;system $_;};'

live free or die
harry

[John Kittel · Accepted solution]

I think the best way is creating a custom shell script with vi and executing it directly from within vi.

Start vi without a filename. Read in the list of filenames, one filename per line. Make each line into an mv command. Write the commands to the shell for execution.

example, read in all files in current directory one filename per line. Add a space at the end of each filename. Change each filename to a move command while duplicating the filename. Change the space at the end of each second filename to .new. Write the script to the shell for execution. Exit vi without bothering to save the script.

$vi
$:r !ls -1
:g;$;s;$; ;
:g;.*;s;.*;mv -i &&;g
:g; $;s; $;.new
:w !sh
:q!

Of course many similar operations are possible, limited only by your skill with vi.

[John Kittel]

I forgot to mention, that example renames every file in curent dir to .new

create a sample directory somewhere with several sample files in it and try it out.

[curt larson_1]

just another way

ls payee*.dat |
sed 's/\(payee\)\(.*.dat\)/\1\2\
\1_plan\2/' |
xargs -i -t -n2 mv

[Muthukumar_5]

Hai,

We can do it with a simple script.

ext=".dat"
name="payee"
new="payee_plan"
i=1

while [[ $i -lt 10001 ]]; do
mv $name$i$ext $new$i$ext
let i=i+1
done

Regards,
Muthukumar

[jonathan2]

There are many ways to do this but I always use very simple software and works with all platform. For checking this software go to google and type- BatchRenameFiles Tool. Check the first result.