script to get user primary group ID

[tom quach_1]

i am writing a script to get user primary GID
and then use case structure to run different
programs depend on the primary GID, but could not figure out how to get primary GID to pass to the CASE structure.
Please help.
Thanks,

Tom

[Peter Godron]

Tom,
field 4 of the /etc/passwd file gives the group id of the user.
Regards

[Robert-Jan Goossens]

# awk -F":" '{ print $4}' /etc/passwd

Regards,
Robert-Jan

[Slawomir Gora · Accepted solution]

Hi,

if you want gid as number try this:
id | awk '{print $2}' | sed 's/gid=\([0-9]*\)(.*/\1/'


ex: of case

GID=`id | awk '{print $2}' | sed 's/gid=\([0-9]*\)(.*/\1/'`

case "$GID" in
'20')
echo "User group"
;;
'3')
echo "This is sys group"
;;
*)
esac

[RolandH]

# id -g # Prints effective GUID
# id -gn # Print GID as name

Examle:

# id -g
3
# id -gn
sys

Script: (We expect GID as number)



GID=`id -g`

case "$GID" in
'3') do somthing;;
'1025') do somthing;;
*) do default;;

esac


Roland

[tom quach_1]

Thank you all for your help.
it's all work out great.
points will be assigned.
case close.
Regards,

Tom