Script question

[Jeff Picton]

Hi

Can anybody tell me how to determine from a day of the week output, how I may classify this as an A cycle, B cycle or C cycle assuming each cycle is of duration 7 days ?

[Massimo Bianchi · Accepted solution]

date +%j will tell you the day number in the year
% is the modulus operator

#!/sbin/sh
TODAY=$(date +%j)
let CYCLE=$TODAY%21
case $CYCLE in
0|1|2|3|4|5|6) echo "Cycle A";;
7|8|9|10|11|12|13) echo "Cycle B";;
14|15|16|17|18|19|20) echo "Cycle C";;
esac;

The only problem in on year-change, since the count is resetted to 0.

But maybe you can cope with it, or write additional code to keep track of the last cycle and change the script itself.

Massimo

[Tim Adamson_1]

Hi Jeff,

Could you elaborate a bit more on what you are trying to achieve. I don't fully understand.


Cheers,


Tim

[Jeff Picton]

Hi Tim

I have a script caljd which calculates the julian day :-

caljd.sh -D -p 1
02

so day_of_week='caljd.sh -D -p 1' gives 02.

From this I need to use a case statement similar to that of Massimo to determine if this is cycle A B or C.

Jeff