search multiple pattern in a file

[Anand_30]

Hi,

I have to search a file for the lines which contains both "ERROR" and "Records". Can anyone please help me to do this. I know "grep -e" option works for multiple patterns but It returns the lines which contains the mentioned pattern. But my requiremnet is that I need only the lines which contains both the above mentioned patterns.

Thanks,
Andy

[Sundar_7 · Accepted solution]

hmm I dont know if there is an "and" in the extended regular expression.

If all you want is to get the job done and could care less about elegance then try this :-)

# grep "ERROR" inputfile | grep "Records"

[Rodney Hills]

Usually I would do the following-

grep -e "ERROR.*Records" -e "Records.*ERROR" file

HTH

-- Rod Hills

[Geoff Wild]

use 2 greps


grep "ERROR" | grep "Records"


Rgds...Geoff

[Jeff_Traigle]

There's probably some fancy regexp stuff you can do with sed or awk or perl, but the following is a pretty simple solution:

grep ERROR filename | grep Records

or

grep Records filename | grep ERROR

[Govind_3]

You can use egrep! saves some typing ;)
Cheers!

[Govind_3]

Sorry I forgot to add. But I agree with others using two greps would be the simplest solution!

[Muthukumar_5]

We can do this with sed / awk as,

sed -n '/ERROR/p;/Records/p' | uniq -d

awk '/ERROR/;/Records/ { print $0 }' | uniq -d

[Julián Esteban Aimar]

Use:
grep ERROR | grep Records