Sum values

[Wagner_17]

Dear friends

Simple and stupid question:

I need to sum values of some files placed in some directory. I use awk to get values like exemple:

# ls -lt avbmon* | awk '{ print $5 }'
13628
13413
13413
13413

Now i have values, but i need obtain total. I try "sum" command, but i don't have succes with sintax. Can anyone help me? Thanks

[TTr · Accepted solution]

awk can sum the numbers for you. Look at
http://forums.itrc.hp.com/service/forums/questionanswer.do?threadId=1218175

[James R. Ferguson]

Hi:

# ls -lt | awk 'END{printf "sum=%-3.0f\n",SUM};{SUM+=$5;print $5}'

Regards!

...JRF...

[Wagner_17]

To obtain in MB values is just to divide by 1024 like below, right?

ls -lt avbmon* | awk 'END{printf "sum=%-3.0f\n",SUM};{SUM+=$5 /1024;print $5 }'
13628
13413
13413
13413
sum=53

[Hein van den Heuvel]

>> To obtain in MB values is just to divide by 1024 like below, right?

That would be KB.
For MB divide by 1024*1024 ( 1048576 )

Also, it is typically best to divide the sum, not the individual components.
Higher precision, and Fewer division (does not matter here).

If you only want the sum of the size, then drop the time sort order from -lt.

try:
ls -l avbmon* | awk 'END{printf "sum=%-3.0f\n",SUM/1048576};{SUM+=$5;print $5 }'

Hein

[James R. Ferguson]

Hi:

To get MB, do:

# ls -lt avbmon* | awk 'END{printf "sum=%-3.2f\n",SUM/1024/1024};{SUM+=$5;print $5}'

...keep the precision as long as you can.

Regards!

...JRF...

[Wagner_17]

Thanks to all!!!