How can i get specifically some lines between a sign ?

[Manuales]

Hi all,
i have this output file:

scheduled Jobs:
Level type Pri
==== (this is a note: first "=")
..xxxx
..xxxx
..xxxx
..xxxx
..xxxx
..xxxx
..xxxx
..xxxx
==== (this is a note: second "=")

Ended Jobs
Level type Pri
===== (this is a note: third "=")
....
...
..
...
....
===== (this is a note: fourth "=")

i want to get only the lines between the first "=" and the second "=", it means, only the scheduled Jobs --> lines: ..xxxx
How can i get them? can i do it with awk? please your support.

[James R. Ferguson]

Hi Manuales:

As you stated your requirement and the pattern of the data:

perl -ne 'if (?^===?...?^===?) {print unless /^===/}' file

Regards!

...JRF...

[Bob_Vance]

Here's an example script using 'awk' :


## cat /tmp/doit

#
awk '
BEGIN {c=0}
{
while (getline) {
if ( match($0 , "===") ) {
c=c+1
if (c>=2) { exit }
continue
}
if (c==0) {
continue
}
if (c==1) {
print $0
continue
}
}
}
END { }
'


Here's a run of it:

## cat /tmp/in | /tmp/doit
..xxxx1
..xxxx2
..xxxx3
..xxxx4
..xxxx5
..xxxx6
..xxxx7
..xxxxE


bv

[Peter Nikitka]

Hi,
in my opinion it is better to keep the awk standard parsing:

awk '/^====/ {mark++}
mark>1 {exit}
mark'

mfg Peter
PS: untested

[Bob_Vance]

@Peter

I've found it easier to use 'awk' in the complex way rather than trying to grok the eccentricities of it's simpler syntax.
Of course, then it just becomes another programming language.

I got used to using it before 'perl' was around.

BTW, your script prints the first "====" line , but I don't know how to fix it :>)


bv

[Dennis Handly]

>BV: I've found it easier to use 'awk' in the complex way rather than trying to grok the eccentricities of it's simpler syntax.

I too started that way but I learn as I go along.

>but I don't know how to fix it :>)

A "next" will cause it to go to the next cycle, think of it as a super "continue":
awk '
/^====/ {
if (++mark > 1) exit
next
}
mark { print $0 }' input-file

[Peter Nikitka]

OK,
other solution without the 'xxxx'-line:

awk 'mark
/^====/ {mark++}
mark>1 {exit}'