How to figure out the LUN Number of an XP disk from xpinfo

[Alzhy]

If a disk/lun is reported by xpinfo say:

target 0f
lun 02

what will be its LUN Number as assigned in CV?

[Alzhy]

Finally figured it out:

Target f (dec 15) x 8 = 120 + Lun 2 = LUN 122

LUN 122 is target f lun 2.

Every 8 LUNs effect an increase in the target value.

[Alzhy]

Hmmm not quite:

The following is supposed to be LUN 1023

# xpinfo -f /dev/rdsk/c140t15d6

Device File : /dev/rdsk/c140t15d6 Model : XP???
Port : CL1A Serial # : 00030015
Target : 0f Code Rev : 5001
LUN : 06 Subsystem : 0004
CU:LDev : 00:20 CT Group : ---
Type : OPEN-V CA Volume : SMPL
Size : 100 MB BC0 (MU#0) : SMPL
ALPA : 00 BC1 (MU#1) : SMPL
Loop Id : 7e BC2 (MU#2) : SMPL
SCSI Id : --- RAID Level : RAID1
FC-LUN : 0000753f00000020 RAID Group : 2-1
Port WWN : 60060e8004753f00 ACP Pair : 2
Disk Mechs : --- --- --- ---


If the formula as I assumed is true, then target should be 127 Dec or 7F Hex. But xpinfo shows target as 0f.

Any ideas of a fool proof formula?

[Torsten. · Accepted solution]

Nelson, you are on the right way. Beyond this value, the "x" in cxtydz will be increased. The correct formula is "bit-based".

Here are 2 links regarding this, perhaps you already know:

http://us-support3.external.hp.com/iv/data/documents/DE_SW_UX_swrec_EN_01_E/Fibre
Channel.pdf

http://www.hp.com/hpbooks/prentice/chapters/0130102229.pdf