unix command sanity check

[john guardian]

could someone please look at the attached text doc and execute the awk command I placed in the attachment and let me know what you get for screen output.

Greatly appreciated. Thanks.

[R.K. # · Accepted solution]

No attachment

[john guardian]

Sorry. The attachment was there. Let's try this again.

Thx.

[R.K. #]

I tried this command on a test server, below is the exact o/p I got:

root# cmd=`which java`
root# echo `/usr/bin/awk '/assemblyIdentity version=/ {print $2} $cmd`

awk: Field $() is not correct.
The input line number is 1.
The source line number is 1.

[john guardian]

OK. So if that's an incorrect usage, what would be the correct form?

[R.K. #]

Hi Again,

Looks like the command is meant to find line containing "assemblyIdentity version=" from the output of "which java".

# which java > /tmp/a1
# awk '/assemblyIdentity version=/ {print $2}' /tmp/a1
# rm /tmp/a1

This should give same results.

[Steven Schweda]

> [...] what would be the correct form?

What are you trying to do?

[john guardian]

I'm attempting to acquire the application major/minor version number w/o having to execute the java -version cmd.

[john guardian]

Note to RK:

Did you actually try to run the cmd you sent?

I'm getting nothing back from it?

If you did, can you send me the cmd used along with the screen output?

[Steven Schweda]

> I'm attempting to acquire the application
> major/minor version number w/o having to
> execute the java -version cmd.

Huh? What is "the application"? Java
itself, or some Java program? If you want
the Java version, what's wrong with "java
-version"?

> What are you trying to do?

Still a mystery. What, exactly, are you
trying to do?