How to exclude a directory using "find"

[Francis Flan]

In a script called by cron i have a line that checks for any new tar files but I want it to exclude a mounted filesystem /share01

This command finds all the tar files
#find / -name '*.tar' -mtime -1

I've been trying to modify it to exclude /share01 but need help.


I've tried this next command but it doesnt exclude /share01:

#find / -name '*.tar' -mtime -1 ! -path "/share01/*"

Any tips?

[Jeeshan]

Hi francis

see this similar thread

http://forums11.itrc.hp.com/service/forums/questionanswer.do?admit=109447626+1210238978644+28353475&threadId=1212067

[Francis Flan]

Thanks ashan,

Ive been looking at similiar threads but cannot get the correct syntax.

I tried the following but no joy
find / -name '*.tar' -path /share01 -prune

Any ideas?

[Jeeshan]

Hi again

So, lets try this command

#find / -type d \( -name DIR1 -o -name DIR2 -o -name DIR3 \) -prune -o
-type d -print


Have fun!!!

[Francis Flan]

The /share01 directory is a remotely mounted NFS directory so I just told it to search local directories instead.

#find / ! -local -prune -o -name '*.tar' -mtime -1 -print

It's a work-around but im pleased.
thanks for your assistance ahsan

[Steve Post]

I don't trust the prune command. Instead I make the list of files and pipe it through grep -v.

LIST=`find / yadda yadda | grep -Ev "^\/excludedir"`

for X in $LIST
do
commands
commands
done

steve