ls command ... getting full path.

[Manuales]

Hi ..
how can i do to get this information when i
use the command ls:

i am located in
pwd
/data/users/files/

the normal out is:
ls -lat:
-rw-r--r-- 1 508 dba 4274 Dec 15 2009 testfile.txt

i wat to get the out as follows:
-rw-r--r-- 1 508 dba 4274 Dec 15 2009 /data/users/files/testfile.txt

if you see, i want to get the out with the full path where the file name is.

how can i get that?
thanks.

[Jose Mosquera · Accepted solution]

Hi,

What about of:
#find /data/users/files/ -type f -exec ls -l {} \;

Rgds.

[Jose Mosquera]

Hi again,

If you need list a specific filename:
#find /data/users/files/ -name testfile.txt -type f -exec ls -l {} \;

For detailed info about "find" and "ls" commands:
#man find
#man ls

Rgds.

[Manuales]

THANKS ... BUT
if i do this:

$ find /data/users/files/ -name * -type f -exec ls -l {} \;
find: missing conjunction
$ find /data/users/files/ -name *.* -type f -exec ls -l {} \;
find: missing conjunction
$


it is not working .. i want to display all the files with full path under the directory /data/users/file , how can i do that?

[Steven Schweda]

> $ find /data/users/files/ -name * [...]

> $ find /data/users/files/ -name *.* [...]

You might try quoting the wildcards:

find /data/users/files/ -name '*' [...]
find /data/users/files/ -name '*.*' [...]

But, if you want all the files, then why use
_any_ "-name" option?


To see what "find" saw:

echo *
echo *.*

[Bill Hassell]

> ls command ... getting full path.

This will provide what you want:

ls -d $PWD/*

[Manuales]

Thanks all, it worked !!!!