About the script

[sunhui]

I have below program to find the process "orapp" and echo the result ,

if
xxxx
then
for x in `ps -ef |grep "orapp" |awk { print $2; }

do
echo $x
done
else
xxxx
fi

now if I want to add one more condition - if the IP address of the process
is 192.168.0.1 ( who -u |awk { print $8} , how can I mix these two
condition into one script ? thx.

[James R. Ferguson]

Hi:

Give you have "X":

# who -u|awk -v x=192.168.0.1 '$8~x {print}'

...will print the matching entry from 'who'.

Regards!

...JRF...

[sunhui]

thx james ,

but how to mix with the above script ? thx

[Kent Ostby]

if
xxxx
then

touch .mytemp
rm .mytemp
ps -ef | awk '/orapp/{print "ps", $2}' > .mytemp
who -u | awk '/192.168.0.1/ {print "who",$7}' >> .mytemp
awk '/^ps/ {keepid[$2]=1;next} {if (keepid[$2]==1) {print $2};}' < .mytem

else
xxxx
fi

[James R. Ferguson]

Hi:

I'm not sure what you want to do. First, using 'grep' to match a process is prone to matching the wrong process. You should use:

# UNIX95= ps -C orapp -o pid,usr,tty

This will find all processes whose *basename* (command) is equal to "orapp". The output of matching processes will include the pid, the user, and the associated tty (if any).

From that, you would match the 'tty' to the 'tty' found in the output of 'who'. You could also match the 'pid' values.

Does this now help?

Regards!

...JRF...

[sunhui]

thx replies,

may be my question is not clear , I just want combine the above two condition into one script , is that possible ? thx