CPU time and elapsed time

[Kris_5]

Hi Floks,

How do I find the time elapsed, CPU time taken for a child process. With timex I am getting real time, but how do I find the CPU time.

TIA

Kris

[Jeff Schussele]

Hi Kris,

If you know the Process ID (PID) - you can do:

#ps -ef | grep PID

And the TIME column will list cumulative execution time.

Rgds,
Jeff

[Helen French]

Hi,

Use 'top' command. Check the "TIME" parameter, that will tell you the number of system and CPU seconds the process has consumed.

You can use Glanceplus too and check the process reports:

# gpm

HTH,
Shiju

[Jeff Schussele]

Kris,

Of course both of these are "real-time" & not elapsed or after the fact times.

If you want those you'll need to install & activate Accounting & then use the acctcom command that searches the /var/adm/pacct file & grep for the command you ran & in here can be found (CPU secs) values.

See the acctcom docs:

http://docs.hp.com/cgi-bin/fsearch/framedisplay?top=/hpux/onlinedocs/B2355-90129/B2355-90129_top.html&con=/hpux/onlinedocs/B2355-90129/00/00/8-con.html&toc=/hpux/onlinedocs/B2355-90129/00/00/8-toc.html&searchterms=acctcom&queryid=20020411-121554

Rgds,
Jeff

[Kris_5]

Hi All,

Thanks for the suggestions. At the moment we haven't installed accounting software (our system engineer thinks it is very much overhead..), so I am trying to find other ways.

Here the example (only) of my case.

$ cat a.sh
#!/bin/sh
echo "xxxx"
sleep 60

$cat b.sh
#!/bin/sh
timex 2>rtime.log a.sh

The b.sh is submitted through cron, so I can't use top or ps -ef effectively.

Kris

[Paula J Frazer-Campbell]

Kris

Try:-

ps -ef | grep "scriptname" >/tmp/timerlog

Place this at secont to last line.

Run it and the cat the timerlog.

HTH

Paula

[Paula J Frazer-Campbell]

Kris

To pick up the pid of your running programme,
within the program:-

runpid=`ps -ef | grep | awk '{print $2}'

echo $runpid


Paula

[Frank Slootweg · Accepted solution]

Perhaps (probably? :-)) I do not understand the question, but the sum of the "user" and "sys" times reported by timex(1) *are* the CPU time.

Some examples:

$ # Hardly any CPU time, i.e. user and sys are (nearly) zero :
$ timex sleep 5

real 5.02
user 0.00
sys 0.01

$ # Nearly all CPU time, i.e. user + sys ~ real:
$ cat ./doit
#! /usr/bin/sh

count=0

while [ count -le 100000 ]
do
((count=count+1))
done
$ timex ./doit

real 8.44
user 5.95
sys 2.48

$