Crontab and print only Monday jobs

[Coolmar]

Hi,

How can I print to the screen only the jobs that run on Mondays?

[Marco A.]

What's your job structure?!... can we see it?!

[Wouter Jagers]

Eek, tough question..

I suppose you could start by checking for "1" and "*" in the 5th field of the crontab like this:

# crontab -l | awk '{if($5~/1/||$5~/\*/){ print}}'

BUT of course we'll be missing things:
- A day field of "0-6" (sunday to saturday) will not be caught.. but I bet with some fiddling that could be fixed.
- A job scheduled to run yearly on May 15th would run next monday. Catching these will be something else.

How detailed do you need to know ? :-)

[Jeff_Traigle]

crontab -l | grep -v "^#" | awk '{if ($5 == 1) print}'

[Jeff_Traigle]

Oops. I'm not thinking in complicated terms this morning. The previous answer covers the bases much better.

[Oviwan · Accepted solution]

Hey

0 for monday

#crontab -l | awk '{ if($5 ~ /[0]/) { print $0 }}'

Regards

[Coolmar]

thanks

[Wouter Jagers]

man crontab:
weekday - The day of the week, 0-6, 0=Sunday

Make sure to look for the right day ;-)

Cheers,
Wout

[Oviwan]

ups my mistake, tested with sunday :)