cut command - specifying multiple delimiters

[jon2]

Peter said
"if you like a solution using shell features only (I did this in ksh): "

Your script starts with "#!/bin/sh"

I suspect this is the problem with your latest post.

BTW did the "read VAR1" work okay in my suggestion. It is odd if it works in mine but not Harrys.

[Peter Nikitka]

Hi Danny,

I just checked:
/bin/sh
a=b.c
echo ${a#*.}

results in 'c' - so the string operators work in the posix shell as well.
Nevertheless:
- Flag your script with
#!/usr/bin/ksh -xe
It will stop at rhe first error and trace the commands.
- check for unprintable characters (like ^M).

mfG Peter

[Nagendra Prasath]

Hi Danny,
I too don have good knowledge, anyway see this code..it'll work.
since i've used only the coloumn number don change the coloumn number with any space.

copy your line "A20051109.0215-0230_SubNetwork=ONRM_RootMo,SubNetwork=SNTDCAUJRNC002,MeContext=SNTDCAUJRNC002_statsfile.xml"
in a file say file1
then do chmod 777 file1
then open a file say solution1.txt and paste the below lines

one=`cat file1 | cut '-c1-9'`
echo "1)$one"
two=`cat file1 | cut '-c11-14'`
echo "2)$two"
three=`cat file1 | cut '-c16-19'`
echo "3)$three"
four=`cat file1 | cut '-c21-93'`
echo "4)$four"
five=`cat file1 | cut '-c95-103'`
echo "5)$five"
six=`cat file1 | cut '-c105-107'`
echo "6)$six"

save and quit
chmod 777 solution1.txt
do ./solution1.txt
it'll give the file in that format.


Also you can alter the code as you require
If you use sed, everything can be finished in one
line.

:)
Prasath