date 5 days from now formatted at %Y-%m-%d

[John Meissner]

Can anyone give a hand. I'm trying to get 5 days from now in this format
2003-10-08
i.e. %Y-%m-%d
i've used the commands
date -d "5 days next"
but it returns
Mon Oct 13 01:00:00 UTC 2003

anyone have a quick one liner (preferably without the use of caljd.sh)?

Any answer will be appreciated

[Pete Randall]

John,

That's interesting - I'm unfamiliar with the -d option. I get:

$ date -d "5 days next"
date: illegal option -- d
Usage: date [-u] [+format]
date [-u] [mmddhhmm[[cc]yy]]
date [-a [-]sss.fff]

So I'm not sure how you're going to do this without caljd.sh.

;^(


Pete

[John Meissner]

ah... sorry... linux.. wrong forum.... but if you want to work on this from a linux stand point i'd still appreciate the help

[Jeff Schussele]

Hi John,

I think you'd have a chance if you use the %j (day of the year) & increment by 5 & convert that back to a standard date. Something like...

var1=$(date +%j + 5)

but that syntax isn't right.

HTH,
Jeff

[A. Clay Stephenson · Accepted solution]

Well, you are making me do this the hard way but:

DT=$(perl -e '($y,$m,$d) = (localtime(time() + (5 * 86400))) [5,4,3]; printf("%04d-%02d-%02d",$y + 1900,$m + 1,$d);'
echo "Date = ${DT}"

I find that
DT=$(caljd.sh -y -S "-" $(caljd.sh -n 5))
echo "Date = ${DT}"
to be much simpler.

You can also download and install the Gnu version of date which will do just about what your original date requests although over a much more limited range than caljd.sh will addrsss.

[A. Clay Stephenson]

oops, I missed a trailing paren; should be:

DT=$(perl -e '($y,$m,$d) = (localtime(time() + (5 * 86400))) [5,4,3]; printf("%04d-%02d-%02d",$y + 1900,$m + 1,$d);')
echo "Date = ${DT}"

[John Meissner]

you are the man Clay! great job - thanks for the magic answer