du command

[Conrad J Wyrzykowski]

Greetings,

I'm trying to retreive files and there sizes using du -a -k which works to well. It goes down the whole folder tree to the smallest file. Is there away to have it stop at the last folder and report the size at that point?

Thanks,
Conrad

[Pete Randall · Accepted solution]

Have you tried the -x option?


Pete

[James George_1]

Hi

Try this

# du -sk * | sort -n Or

# du -sk * | sort -rn

Rgds / James

[Cem Tugrul]

Conrad,
du -ks * |sort -n
would be solution for you...
Good Luck,

[Conrad J Wyrzykowski]

Great,

Pete's -x option is the best so far. I now need to find a way to determine if the very first level returned is a directory then to return the files inside it. I may need to stick with the -a option and then take the file into ACCESS or something and force it to group the files that I need. More thought required.

Thanks.

[Jeff Schussele]

Hi Conrad,

This is what I use:

du -akx | sort -rn | more

This puts the grand total right up top.
Plus shows you the "hogs" up there as well.

HTH,
Jeff

[Conrad J Wyrzykowski]

Tkx Jeff,

I like this better. How would you sort the file so that it is done based on the path rather than the size?

Conrad

[James R. Ferguson]

Hi Conrad:

To use Jeff's suggestion but sort the output using the filename (the second field), simply do:

# du -akx | sort -k2 | more

See the 'sort' manpages for more information.

Regards!

...JRF...

[Jeff Schussele]

Well...you'd have to sort differently- here's a sort EX:

du -akx | sort -rn | sort -k 2,2 | more

This will sort second field - i.e. path & THEN the size within.
Flip those around & you'll get size then path.




HTH,
Jeff

[Conrad J Wyrzykowski]

Thanks all, I went with Jeff's script and the rest will have to be done manually.