error in include_std/limit and include_std/rw/iterator

[dodo_ind]

I get following compile time errors on HP ITANIUM machine
"/opt/include_std/limit", line 268: error # 2321: data member initializer is not allowed
_RWSTD_STATIC_CONST (bool, is_specialized = false);

"/opt/include_std/rw/iterator", line 119: error # 2247: class template "std::iterator_traits" has already been defined
struct iterator_traits

aCC version: HP C/aCC B3910B A.06.12 and OS version is 11.23

I'm compiling using -Aa option along with -D__HP__, -D_TEMPLATE, -D_RUNTIME
Missing any compiler flags or include path? Application uses INFORMIX version 2.9.

Any help highly appreciated

[Dennis Handly]

What does your compile line look like?
What does your source look like?
Are you using any evil macros.

The latest version is A.06.25.01.

[dodo_ind]

Thanks Dennis for your response
compile line is:

aCC -I/opt/informix/incl/esql/ -I/home/test/SERVICE/src/../../incl -I. +DAportable +p -g +Z -Aa -D__HP__ -D_DEBUG -D_TEMPLATE_ -D_RUNTIME_ +inst_implicit_include -D_SERVICE_VER_=\"434D.12\" -L/home/test/service/src/../../lib -D_TEMPLATE_ -o /home/test/SERVICE/src/../exe/ser_bin service_chg.c -lservice -l servicezip /opt/informix/lib/esql/libifos.a /opt/informix/lib/esql/libifgen.a /opt/informix/lib/esql/libifgls.a -ldl -lm -lsec -lelf /opt/informix/lib/esql/libifglx.a

I'm not able to find out which source file is including limit file. -lservice and -l serviceziplibs are two libs provided by other developers for ITANIUM version

[Dennis Handly]

>aCC +DAportable -Aa +inst_implicit_include

+DAportable isn't valid, remove it.
Replace -Aa by -AA.
Remove the obsolete template style option: +inst_implicit_include

>I'm not able to find out which source file is including limit file.

You might try -H but I'm not sure your old aCC6 supports it.

[dodo_ind]

Made changes as suggested by you...still I get same error.

I tried adding following in the compile line:
-D_PROTOTYPES -D_XOPEN_SOURCE_EXTENDED _D_STDC -D_INCLUDE_HPUX_SOURCE -D_INCLUDE_POSIX4_SOURCE.
I got different error that some APIs such as _iqconnect, _iqstmt that are part of INFORMIX are undefined

error message:
"CFunc.ecpp", line 112: error # 2020: identifier "_iqconnect" is undefined
_iqconnect(0, dName, (char *) 0, (char *) 0, 0);


I have included informix lib path in the compile line...still it is not able to find these APIs...
I'not sure whether previous error is resolved or this error comes before that....

[Dennis Handly]

>Made changes as suggested by you. still I get same error.

(These were only to clean up things.)

>I tried adding following in the compile line:
-D_INCLUDE_HPUX_SOURCE -D_INCLUDE_POSIX4_SOURCE

You are not allowed to use these internal defines. Use: -D_HPUX_SOURCE -D_POSIX4_SOURCE

>I got different error that some APIs such as _iqconnect, _iqstmt that are part of INFORMIX are undefined

Which header should they be defined in?

>I have included informix lib path in the compile line. still it is not able to find these APIs.

You need use -I not -L/-l for header files. You have two, do you need to add more?

[dodo_ind]

I resolved the error by including correct header file.
But I got unsatisfied symbol error. When I added -c flag, this error disappeared.
The binary also got generated but it is of very small size than its normal size
I get error when I try to execute this binary:
/usr/bin/sh: service: Execute permission denied

I tried chmod 777. still it doesn't works...

I also used -lstd and -lstream to resolve some unsatisfied symbol error.
The code was written for HP-UX machine and I'm trying to make it work in ITANIUM

[Dennis Handly · Accepted solution]

>When I added -c flag, this error disappeared.

It also doesn't link, don't add -c.

>I also used -lstd and -lstream to resolve some unsatisfied symbol error. I'm trying to make it work in Integrity.

The default on Integrity is -AA. You should NOT be using -lstd nor -lstream.

What are your unsats?

[dodo_ind]

Thanks Dennis. Will remove -c

>What are your unsats?
I don't understand your question. Could you please explain 'unsats'

[Dennis Handly]

>Could you please explain 'unsats'?

Short for "unsatisfied symbol".