find command - file modification date

[Renetta Brown_1]

I'm trying to find and list files (eventually remove them) that have a modification/creation date of previous day. I'm trying
find /u01/app/oasist/pbin/*.log -mtime -1 -exec ls -la {} \;
but it's giving me a listing of files from today and yesterday.

[DIPAK KUMAR ROY]

find /u01/app/oasist/pbin/*.log -mtime +1 -exec ls -la {} \;


Thanks

[Renetta Brown_1]

Thanks, but that doesn't list the files from yesterday either, but, it does exclude those from today and yesterday. (lists 1 that I have from April of 2002)

maic_dev2:/u01/app/oasist/pbin> find /u01/app/oasist/pbin/*.log -mtime +5 -exec ls -la {} \;
-rwxr-xr-x 1 oasis dba 0 Apr 11 2002 /u01/app/oasist/pbin/bill_eng.log

I'd like to only get/remove the file from yesterday, December 16th.

-rw------- 1 root sys 15092 Dec 16 20:23 /u01/app/oasist/pbin/12_16_103.log
-rw-r--r-- 1 oasis dba 875 Dec 17 10:19 /u01/app/oasist/pbin/12_17_103.log

[DIPAK KUMAR ROY]

Please check your command. You typed it wrong. ( +5 instead of +1)

Thanks

[RAC_1]

Whay find?

ll -ct|grep -i "Dec 16"

[Renetta Brown_1]

Same result with +5 or +1:
maic_dev2:/u01/app/oasist/pbin> find /u01/app/oasist/pbin/*.log -mtime +1 -exec ls -la {} \;
-rwxr-xr-x 1 oasis dba 0 Apr 11 2002

maic_dev2:/u01/app/oasist/pbin> find /u01/app/oasist/pbin/*.log -mtime +5 -exec ls -la {} \;
-rwxr-xr-x 1 oasis dba 0 Apr 11 2002 /u01/app/oasist/pbin/bill_eng.log

[Pete Randall]

You could always use grep to search for the specific date. You could also use the touch command to create reference file(s) with the correct time(s) and the "-newer" option of find to locate files that fall between those correct times.


Pete

[john korterman]

Hi,
how about this:

# find /u01/app/oasist/pbin/*.log -type f \( -mtime +0 -a -mtime -2 \) -exec ls -ltr {} \;

regards,
John K.

[Renetta Brown_1]

I want the process automated, so, I don't want to supply date every time. (or have to code something to supply it)

[Renetta Brown_1]

Thanks, but this one didn't retrive anything...
maic_dev2:/u01/app/oasist/pbin> find /u01/app/oasist/pbin/*.log -type f \( -mtime +0 -a -mtime -2 \) -exec ls -ltr {} \;
maic_dev2:/u01/app/oasist/pbin>

[RAC_1]

export YESTERDAY=$(TZ=$(date +%Z)+24; date '+%b %e')

ll|grep -i ${YESTERDAY}

[Renetta Brown_1]

???

maic_dev2:/u01/app/oasist/pbin> ll|grep -i ${YESTERDAY}
grep: can't open 16

[RAC_1]

export YESTERDAY=$(TZ=$(date +%Z)+24; date '+%b %e')

ll|grep -i "${YESTERDAY}"

note double quotes

[Renetta Brown_1]

Success! Thanks!

[Helen French]

Here you go:

# find /u01/app/oasist/pbin/*log -mtime 1 -exec ls -al {} \;

Note the "1" and not +1 or -1. This what each one of it will do:

1 - between 24 and 48 hours old
+1 - 48 hours or older
-1 - within 24 hours

Please remember that -mtime calculates times in 24 hours and not in actual *days* as we calculate.

[Renetta Brown_1]

Thanks for that info...

[Dave La Mar]

Renetta -
This is the find command I use for a daily cleanup of one of out /tmp directories.

find /tmp/ -type f -mtime -1 > output_file

This is for all files within the last 24 hours.
To eliminate today's:

grep -v "date '+%b %m'" output_file > delete_file

Of course your cript will have to sed or cut the file name field.

Best of luck.

Regards,

dl

[Dan_242]

Great! Is there a way to list it the long way? Like this :

-rw-r--r-- 1 rahxgb users 3552 Apr 4 2000 mailqmon.log

[Dan_242]

Sorry, I don't think that questions was very clear. What I ment to ask was if there was a way write to output_file that would list the the long format as in "ls -al"...

- Dan