Find MIN and MAX

[Ralf Buchhold]

Hello
i want to find out the min and max form:
01.01.05 3106 3279
02.01.05 3105 3279
03.01.05 3105 3279
04.01.05 3113 3279
05.01.05 3114 3279
06.01.05 3116 3279
07.01.05 3116 3279
08.01.05 3114 3279
09.01.05 3114 3279
10.01.05 3114 3279
11.01.05 3117 3279
12.01.05 3120 3280
13.01.05 3121 3280
14.01.05 3125 3281
15.01.05 3124 3281
16.01.05 3121 3281
17.01.05 3121 3281
18.01.05 3123 3281
19.01.05 3125 3282
20.01.05 3127 3270
21.01.05 3127 3271
22.01.05 3134 3273

In this example:
MIN1=3105
MAX1=3134
MIN2=3270
MAX2=3282
Thanks
Ralf

[Stephen Keane]

Use sort -n -k

then head -1 for min and tail -1 for max.

Where keydef determines which field (column) you are sorting on

[Peter Godron · Accepted solution]

Ralf,
how about:
#!/usr/bin/sh
echo "top = `sort -k$1,$1n $2 | head -1 | cut -d' ' -f$1`"
echo "min = `sort -k$1,$1rn $2 | head -1 | cut -d' ' -f$1`"

if saved as a.sh and the data is in a.dat
./a.sh 2 a.dat [ for the second field ]
./a.sh 3 a.dat [ for the third field ]

Regards

[Stephen Keane]

If data is in fred

# MIN1=`cat fred | sort -n -k2,2 | head -1 | awk '{ print $2 }'`
# MAX1=`cat fred | sort -n -k2,2 | tail -1 | awk '{ print $2 }'`
# echo $MIN1
3105
# echo $MAX1
3134
# MIN2=`cat fred | sort -n -k3,3 | head -1 | awk '{ print $3 }'`
# MAX2=`cat fred | sort -n -k3,3 | tail -1 | awk '{ print $3 }'`
# echo $MAX2
3282
# echo $MIN2
3270

[Elmar P. Kolkman]

If you're using awk anyway, why not:

awk 'NR==1 { min1=$2; max1=$2;min2=$3;max2=$3}
{ if (min1 > $2) { min1 = $2 }
if (min2 > $3) { min2 = $3 }
if (max1 < $2) { max1 = $2 }
if (max2 < $3) { max2 = $3 }
}
END { printf "Min1=%d Max1=%d\nMin2=%d Max2=%d\n",min1,max1,min2,max2 }'

[Peter Godron]

Ralf,
did these answers solve your problem?
If not can you please update the thread.

Please assign points and close the thread, identifying the solution.
Many Thanks