generating delay based on the counter value

[Anand_30]

Hi,

I have the following script:

c=1
while [ $c -le 3000 ]
do
cat ${myfile}|while read A B
do
"something"
c=`expr $c + 1`
echo $c
done
done

I want to generate 1 sec delay for every 200th count of the counter. Can anyone please help me in accomplishing the task.

Thanks,
Andy

[Steven E. Protter · Accepted solution]

c=1
while [ $c -le 3000 ]
do
cat ${myfile}|while read A B
do
"something"
c=`expr $c + 1`

if [ $c -eq 200 ]
then
sleep 1
fi

echo $c
done
done

You can reset the counter if you intent is to do that or you can do some division to see if the number is divisible by 200. You you can set a second counter like this.

c=1
d=1
while [ $c -le 3000 ]
do
cat ${myfile}|while read A B
do
"something"
c=`expr $c + 1`
d=`expr $d + 1`

if [ $d -eq 200 ]
then
d=1
sleep 1
fi

echo $c
done
done


Do note that this expression type is considered obsolete:

d=`expr $d + 1`

It should be d=$(expr $d + 1)'

For new scripts.

[Seth Parker]

I've always been fond of the modulus, so how about this:

c=1
while [ $c -le 3000 ]
do
cat ${myfile}|while read A B
do
"something"
c=$(expr $c + 1)
[ $(expr $c % 200) -eq 0 ] && sleep 1
echo $c
done
done

This way, the sleep only happens when the remainder of $c / 200 is 0.

Regards,
Seth