get a string in a line

[idi]

hi, anybody help me

how to get a string in a line hp ux?

'i want to solve this problem' and i want to get 'solve' but how?

[Robert-Jan Goossens]

could you post an example ?

[Muthukumar_5]

You can use awk, sed for getting string in a line. grep can used to search it. post example input and output you want.

hth.

[Giacomo TOTTI]

Hi,
if you simply want to get a line in a file, use a grep command, it's a simplier way!!

i.e.

grep test file

(if you want to search a string with a test word)

enjoy

Giacomo

[Alessandro Pilati]

if you know the position of the string use:
awk '{ print $4 }'

[idi]

LINE IS: 'i want to solve this problem'
and STRING IS: 'solve'
so how can i get these string?

note: i just want to get the string 'solve'
i dont want to get line (grep command is not suitable for this question)

[Muthukumar_5]

You can try as,

echo "i want to solve this problem" | sed '/solve/!d;s/^.*solve.*/solve/'

or

echo "i want to solve this problem" | grep 'solve' | sed '/solve/!d;s/^.*solve.*/solve/'

hth.

[Muthukumar_5]

It is easy that. You have to search the line with solve string and change into 'solve' that is all. Do it with awk as,

echo "i want to solve this problem" | awk '/solve/ { print "solve";}'

hth.

[Leif Halvarsson_2]

Hi,
If you want to search for strings in plain text files you can use "grep -q".


-q (Quiet) Do not write anything to the standard
output, regardless of matching lines. Exit
with zero status upon finding the first
matching line. Overrides any options that
would produce output.

Then you can use an "if" condition to print out anything you want depending on hit/non hit.

[Giacomo TOTTI]

OK,
if the word "solve" is always on the fourth position, than:

grep solve file| awk '{print $4}'

regards,

Giacomo

[Alessandro Pilati]

Idi,
echo "i want to solve this problem" | awk '{ print $4 }'

[idi]

Thank you so much all you, But actually my real problem is, I have a text which i gave 'attachment'

and firstly i want to find 'May 13 2003' string in this text and after i want to clear the lines which, dates are before 'May 13 2003'

Thank you again so much

[john korterman]

Hi,
try this slightly reused awk statement:

# awk '/May 13/,/\$/' orgfile > newfile

and then
# diff orgfile newfile
to check if it is ok.

regards,
John K.

[Muthukumar_5]

You can try as,

## CODE ###
FILENAME=testfile
LINE=$(grep -n 'May 13.*2003' $FILENAME | cut -d':' -f1)
tail -f +${LINE} $FILENAME
##

hth.

[David Child_1]

This isn't going to be an easy one-liner. You need to pull the time stamps, then compare. First off, the lines do not all have the same number of columns so try the following to parse the timestamps;

awk '{ print $(NF-3),$(NF-2),$(NF-1),$NF }' file

Once you have the timestamps you will need to do some coding where you compare the year, then month, then day.

David

[H.Merijn Brand (procura]

Use grep -w -c

lt09:/home/merijn 102 > grep -c -w merijn /etc/passwd
1
lt09:/home/merijn 103 > grep -c -w merlijn /etc/passwd
0
lt09:/home/merijn 104 >

Since you want returned something you know, it doesn't matter if you get that word or "1"

If you *do* mind, try this:

sh-3.00$ var=merijn
sh-3.00$ grep -q -w $var /etc/passwd && echo $var
merijn
sh-3.00$ var=merlijn
sh-3.00$ grep -q -w $var /etc/passwd && echo $var
sh-3.00$

Enjoy, Have FUN! H.Merijn