How to display or cat 10th line to 20rth line of a text file have 100 lines in HP UNIX

[Mannoj]

How to display or cat 10th line to 20rth line of a text file have 100 lines in HP UNIX?

[Ganesan R]

Hi,

Use this command.

awk -v line=10 "NR==line" file_name -> to display 10th line.

awk -v line=20 "NR==line" file_name -> to display 20th line

[Ganesan R]

Hi,

You can also use this command.

sed -n '10 p' < file name -> to display 10th line

sed -n '20 p' < file name -> to display 20th line

[Oviwan]

you can use sed:

sed -n '10,20p' >

source: http://www.student.northpark.edu/pemente/sed/sed1line.txt

[V. Nyga]

cat fstab.org | awk '{if (NR >9) {print $0}}' | awk '{if (NR <21) {print $0}}'

HTH
Volkmar

[Mannoj]

Excellent as this is my first day to register on to this blog... that was a gud solution !!!!

[V. Nyga]

Ups - sorry for the first post:

cat fstab.org | awk '{if (NR >9) {print $0}}' | awk '{if (NR <12) {print $0}}'

HTH
Volkmar

[V. Nyga]

has to be of course :-)

V.

[Oviwan]

so don't forget so say thanks with hp points ;)

[Ganesan R]

Hi Manoj,

You can play this trick with head and tail also. see below.

# head -10 filename |tail -1 -> display 10th line
# head -20 filename |tail -1 -> display 20th line.

[sreekanthtm]

Hi Ganesan,...

Please read question again...
He wants display lines from 10 to 20( 10,11,12....up to 20). Not exactly 10th and 20.

Rgds
Sreekanth

[Ganesan R]

Yes Sreekanth, I misread the question.

Manoj, use this command.

#sed -n '10,20p'

[Hein van den Heuvel]

awk 'NR==10,NR==20'

perl -ne 'print if $.>=10; last if $.>=20'

Hein.

[Mannoj]

Hi ... thanx to every one who replied...

I used sed -n '10,20p' which matched my requirement..

Excellent job !!!!