How to get count total size of files under dir

[diwa]

Hi,

as per one requirement i need to give the total size estimates of files under certain dir.
i want some simple command which can give me the correct total size of all files in bytes.
Is there any way that i can get size in MB or GB? If there are any simple way to do this then it will be very help ful for me?

Thanks

[Pete Randall]

Try du:

du -sk /directory_name


Pete

[James R. Ferguson]

Hi:

# du -kxs /directory

...will return the total in 1K (1024) bytes

Regards!

...JRF...

[spex · Accepted solution]

> Is there any way that i can get size in MB or GB?

$ du -skx /mydir | awk '{printf("%.2f bytes, %.2f mbytes, %.2f gbytes\n",$1,$1/1024,$1/1048576)}'

PCS

[Sp4admin]

Hello,

You could do a "du -s" for the total of in the directory you are in or "du -s *" for all the the files in the directory.

sp,

[Ernesto Cappello]

Hi Diwa

du -sk .

BR.
Ernesto

---------------------------------------------
MAN du:

NAME
du - summarize disk usage

DESCRIPTION
The du utility writes to standard output the size of the file space allocated to, and the size of the file space allocated to each subdirectory of, the file hierarchy rooted in each of the specified files. The size of the file space allocated to a file of type directory is defined as the sum total of space allocated to all files in the file hierarchy rooted in the directory plus the space allocated to the directory itself. This sum will include the space allocated to any extended attributes encountered.

Files with multiple links will be counted and written for only one entry. The directory entry that is selected in the report is unspecified. By default, file sizes are written in 512-byte units, rounded up to the next 512-byte unit.

[James George_1]

Hi

# cd /dir

# du -sk * | sort -rn

Rgds / James

[diwa]

Hi,

Thanks a ton to all.
Hi Spex,

Your Awk cmd is working fine. As JRF told du -ksx will return total in Kb, therefore can update your cmd like in place of bytes i am putting KB, please correct me if i am wrong:

$ du -skx /mydir | awk '{printf("%.2f Kbytes, %.2f mbytes, %.2f gbytes\n",$1,$1/1024,$1/1048576)}'

[James R. Ferguson]

Hi:

Rather than code your constant as 1048576 in:

# du -skx /mydir | awk '{printf("%.2f Kbytes, %.2f mbytes, %.2f gbytes\n",$1,$1/1024,$1/1048576)}'

...it is clearer to do:

## du -skx /mydir | awk '{printf("%.2f Kbytes, %.2f mbytes, %.2f gbytes\n",$1,$1/1024,$1/(1024*1024))}'

This makes the calculation much more obvious and is less likely to be wrong because of a typographical error.

Regards!

...JRF...

[diwa]

Hi JRF,

Thanks a lot. Now it is fine for me.

[diwa]

Hi JRF,

Thanks a lot. Now it is fine fro me.