How to make grep to match start of line.

[Prasad Joshi]

Hi All,

I am using this command
/opt/ignite/binpa/print_manifest.
It is showing very long output.

I want to search for string "HP" but, it should be at the start of the line only.

How can i use grep in this case?

Thanks & regards,
Prasad

[Arunvijai_4]

Hi Prasad,

You can rather store output of /opt/ignite/binpa/print_manifest to a file and do a search with "vi". print_manifest gives a detailed output of all neccessary stuffs.

-Arun

[RAC_1]

/opt/ignite/binpa/print_manifest | grep '^HP'

grep -i '^HP' ->

[RAC_1]

/opt/ignite/binpa/print_manifest | grep '^HP'

grep -i '^HP' -> To ignore case

[Arunvijai_4]

Hi Prasad,

# /opt/ignite/binpa/print_manifest | grep -i '^HP'

Should be useful. But, look at everything in detail like,

# /opt/ignite/binpa/print_manifest | more


-Arun

[Muthukumar_5]

/opt/ignite/binpa/print_manifest | grep -E "^HP"

will give it.

^ - to give start of line.

--
Muthu

[Muthukumar_5 · Accepted solution]

There is a possiblity to have spaces infront of HP in the line start. To get that also then use as,

/opt/ignite/binpa/print_manifest | grep -E "^[ ]*HP"

Will help.

You can use awk or perl or sed too.

--
Muthu

[Prasad Joshi]

Hi All,

Thanks for instant replay.

This did the job
/opt/ignite/binpa/print_manifest | grep -E "^[ ]*HP"

Special thanks to Muthukumar


Thanks & regards.
Prasad