how to retrive the server name only from servername.x.y.com

[Hanry Zhou]

I have the variable A=servername.x.y.com
but I just want to retrive "servername" portion from the variable, what is the command?
Thanks,

[Patrick Wallek]

Well you could use awk

NAME=$(echo ${A} | awk -F . '{print $1}')

or you could use cut:

NAME=$(echo ${A} | cut -d . -f 1)

[Rick Garland]

echo $A | awk -F. '{print $1}'

This will return 'servername'

[John Palmer]

You could also use the shell's inbuilt parameter substitution which is more efficient as it doesn't have to fork a new process...

If $A contains "servername.x.y.com" then the command:

B=${A%%.*}

gives you "servername" in $B. This works by removing the first "." and everything after it. See man sh-posix for details.

Regards,
John