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12-03-2002 12:50 PM
12-03-2002 12:50 PM
int overflow
Hi all,
I was wondering what would happen If I did the following declaration and initialization:
signed char a = 256;
Since a char is only 8 bits its maximun is 255.
I've tested this printf("%x\n", a); and got zero as a result...??
What does really happen when we overflow the system defined limits of basic integer types?
I assume the same would happen when I do for example:
short s_int = 65536;
The answer of printf("%hd\n", s_int); is 0
If I did
short s_int = 65537;
then the answer will be 1.
Is there a way to predict this behaviour...?
What really happens when we overflow these int types...?
Thanks a lot to everybody in advance....
Max
I was wondering what would happen If I did the following declaration and initialization:
signed char a = 256;
Since a char is only 8 bits its maximun is 255.
I've tested this printf("%x\n", a); and got zero as a result...??
What does really happen when we overflow the system defined limits of basic integer types?
I assume the same would happen when I do for example:
short s_int = 65536;
The answer of printf("%hd\n", s_int); is 0
If I did
short s_int = 65537;
then the answer will be 1.
Is there a way to predict this behaviour...?
What really happens when we overflow these int types...?
Thanks a lot to everybody in advance....
Max
1 REPLY 1
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12-03-2002 12:57 PM
12-03-2002 12:57 PM
Re: int overflow
The behavior of integer overflow is undefined although what you have found is typical. The proper way to deal with this is to use the limits found in /usr/include/limits.h which define the maximum and minimum values for vaarious data types on your platform.
If it ain't broke, I can fix that.
The opinions expressed above are the personal opinions of the authors, not of Hewlett Packard Enterprise. By using this site, you accept the Terms of Use and Rules of Participation.
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