Kill processes that follow

[tyro]

The file attached shows the status of multiple processes running on my machine.

I want to kill all the processes that are listed after the 'Marker Process', i.e. Process4, Process5, Process6.

For this I need to extract the process ID of the processes listed after the 'Marker Process'.

Can someone please suggest a way to extract those PIDs. I know that awk '{print $9}' will get me the PIDs, but I only want the ones listed after the 'Marker Process'.

The next line in my code would read:
kill -9 $killproc

where killproc has the process ids of the above mentioned processes.

Thanks

[Peter Godron]

Hi,
can you use the following to extract the data:
cat | sed -n "/MarkerProcess/,/^$/n;p"
This should extract all the lines from MarkerProcess onwards.
You can then awk the process id and you should be done.
Hope this solves the problem.
Regards

[Keith Bryson · Accepted solution]

Hello there

This one line should work (/tmp/input is the output you enclosed in your posting):

cat /tmp/input | sed -n '/MarkerProcess/,//p' | grep -v "MarkerProcess" | awk {'print $9'} | xargs kill -9

I'm assuming here though that you will only have Processx lines after the MarkerProcess line? If not, you can enter another grep to ensure you only have Processx lines to kill:

cat /tmp/kfb.input | sed -n '/MarkerProcess/,//p' | grep -v "MarkerProcess" | grep "^Process" | awk {'print $9'}

All the best - Keith

[Keith Bryson]

Sorry, that last line should have included the xargs command:

cat /tmp/input | sed -n '/MarkerProcess/,//p' | grep -v "MarkerProcess" | grep "^Process" | awk {'print $9'} | xargs kill -9

Have fun - Keith

[Steven E. Protter]

Might be able to feed the process id's to this gkill. You take out the two interactive steps, and it is an automated, process killer.

This is a very powerful tool. Read the code, be familiar with it.

SEP

[tyro]

Hi Peter,
I was not able to follow what the line you entered does. Would really appreciate if you could explain what '/^$/n;p' does.

When I tried using it in my code, and redirected the output to another file, I got an output with the MarkerProcess missing.

But its also listing Process1, Process2 and Process3. I only want Process4, Process5 and Process6 (that follow after MarkerProcess) to get listed. How do I get rid of those ?

Thanks

[tyro]

Keith,
That line was beautiful. Its solved my problem in a jiffy.

Trouble is, now I really want to know how it works. :-)

cat /tmp/input | sed -n '/MarkerProcess/,//p' | grep -v "MarkerProcess" | awk {'print $9'} | xargs kill -9

Understood that the grep -v command helped us exclude 'MarkerProcess' from the search.

Why did you use the ',//p' ? What does it do ?

Google showed me that:
# To print only lines which match regular expression (emulates "grep")
sed -n '/regexp/p'

But sed -n '/MarkerProcess/p' did not work. It gave me a bad argument error. :-S Curious.

Thanks

[tyro]

Hi Steven,
Thanks for the gkill. Really appreciate the idea.

Keith made the moves really swift. :-))