language and scripting

[Soumya Poddar]

I am new in Unix
please forgive me if my question looks
very simple to you.


I am writing this

program in c
.....
while((c=getopt(..,..,..))!=-1)
{
...
...
......
}

but my two of my options in my program need more than two arguments
how do I do it please help.

[Laurent Menase · Accepted solution]

#include
#include
main (int argc, char *argv[])
{
int c;
int bflg, aflg=0, errflg=0;
extern char *optarg;
char *ifile,*ofile;

extern int optind, optopt;
while ((c = getopt(argc, argv, ":abf:o:")) != -1)
switch (c) {
case 'a':
aflg++;
break;
case 'f':
ifile = optarg++;
if (optarg[0]=='-')
errflg++;
else
{
ofile = ++optarg;
optind++;
}
break;
case ':': /* -f or -o without arguments */
fprintf(stderr, "Option -%c requires an argument\n",
optopt);
errflg++;
break;
case '?':
fprintf(stderr, "Unrecognized option: - %c\n",
optopt);
errflg++;
}
if (errflg) {
fprintf(stderr, "usage: . . . ");
exit (2);
}
printf("f= %s..%s..%d\n",ifile,ofile,aflg);
for ( ; optind < argc; optind++)
printf("%d %s\n",optind,argv[optind]);
}

[Soumya Poddar]

Thank you

[Soumya Poddar]

sir
your program is not taking two arguments
i takes first arguments properly but for the second one the program takes it as a string except the first two charecters of the first argument..
I want to mean that

if input is

./a.out -f 4567 7890

the output gets
f= 4567..67..0

so it does not taking the second argument


please help sir

[Laurent Menase]

indeed it is
case 'f':
ifile = optarg;
if (optarg[0]=='-')
errflg++;
else
{
ofile = argv[ optind++];
}
break;


sorry

[Soumya Poddar]

thank you
sir
it helps me a lot

[Soumya Poddar]

actually here the getopt does not parse the argument by it-self fully
but our intervention is needed there
is there any way to avoid this
is there any function of technique is there

plese help me sir

[Laurent Menase]

can you clarify?
I am not sure I understand what you are trying to do.

just an example could help

[Soumya Poddar]

actually

we write
while((c=getopt(...,...,":abc:")!=-1)
{
....
....
....
}

here the getopt can easily understand that the option c should need a argument with it
hence, it searchs for the argument when it sees the option -c in the string of one of it's strings stored in argv[] vector.

just like that do we have any other kind of option where the function it self searches for the two arguments or the argument list.


please help
sir

if u need any more clarification please reply me

[Laurent Menase]

I am sorry I don't follow

./a.out -f toto tata -c arg1 arg2 arg3 arg4 ... -z
you want to get the list of -c args?