Log message of cron.

[Rajesh SB]

Hi,

In cron log, noticed 3rd line in below.

CMD: /opt/dispatcher.sh > /dev/null 2>&1
oper 19551 c Wed Sep 17 15:25:00 EDST 2003
oper 19551 c Wed Sep 17 15:25:00 EDST 2003 rc=1
oper 19550 c Wed Sep 17 15:25:03 EDST 2003

I am thinking rc=1 must be a retrun code 1 from script. Am I right?

Any pointer on this?

Thanks in advance.

Cheers,
Rajesh

[Umapathy S]

Rajesh,
rc=1 is the return code from the shell/script. /opt/dispatcher.sh returns 1 to the cron job which is shown in cron log.

HTH,
Umapathy

[T G Manikandan]

you are right rc is the return code of the script.

most probably due to the environmental variables not defined.

make sure that you define all the env variables inside the cron script.


Thanks

[Pete Randall]

Rajesh,

I agree that this is a return code. The only suggestion I have is to stop redirecting stderr and stdout to see if you can find out what caused the rc.


Pete

[Pete Randall]

Rajesh,

Is user "oper" allowed to use cron? Do they appear in /var/adm/cron/cron.allow?


Pete

[Steven E. Protter]

The usual problem with cron scripts is the script calls a program that isn't on its PATH or some other environment variable isn't set the way its expected.

Two ways to deal with it. Set the PATH in the script along with other environment variables, or use the full path of all the commands in the script.

SEP

[Rajesh SB]

Hi experts,

Thanks for your prompt response on this issue.
I am succeeded to analyze this error. I am right. Scheduled dispatcher.sh shell script is exiting with return code i.e. rc=1.

Really, I apreciate your various ideas to analyse error.

Cheers,
Rajesh SB