loop counter script

[Ratzie]

How do you go about doing a loop that counts from 00001 to 99999

This errors out...

echo $COUNT
while [ "$COUNT" -lt "1" ]
do
COUNT=`expr "$COUNT" + 00001`
# echo $COUNT"," >> $DATAFILE
echo $COUNT","
done

[Jean-Luc Oudart · Accepted solution]

initialise COUNT :

typeset -i COUNT
COUNT=0

Rgds,
JL

[Victor BERRIDGE]

You havent initialized COUNT for a start...


Good luck

Victor

[Ratzie]

Sorry but newbie, intialize?
When I added to my script I get an error...

#!/bin/sh

#Variables
DATAFILE=/tmp/count.file
initialize COUNT:
typeset -i COUNT
COUNT=0


#start script
#does counter equal 99999
echo $COUNT
while [ "$COUNT" -lt "1" ]
do
COUNT=`expr "$COUNT" + 00001`
# echo $COUNT"," >> $DATAFILE
echo $COUNT","
done


./count_to.sh[20]: initialize: not found.

[A. Clay Stephenson]

You don't need expr and you should avoid [ rather then [[. In the POSIX or Korn shell if [[ ]] is an internal test whereas if [] calls the external test command. Also (( .. )) is an implicit let for numeric operations.

typeset -Z5 COUNT=1
typeset -Z5 STOP=99999
while [[ ${COUNT} -le ${STOP} ]]
do
echo "${COUNT},"
(( COUNT +=1 ))
done

[Michael Schulte zur Sur]

Hi,

initialize means setting a variable to a defined value, in your case COUNT=1.

greetings,

Michael