ls -laR; du; | sort per directory to show decending order of file sizes from current directory

[Bill McNAMARA_1]

Where do I start to do something like this;

Rewards for all suggestions!

Later,
Bill

[Andreas Voss]

Hi,

for du try:

du -a | sort -n

for ls try:

ls -laR | sort -k5n

Regards

[Santosh Nair_1]

Not really sure if this is what you're looking for but how about:

find . -type -d -exec du -sk {} \; |sort -n

-Santosh

[Stefan Farrelly]

Hows this;

cd
du -k . | sort -nr | more

[Robin Wakefield · Accepted solution]

Hi Bill,

This will format it on a per directory basis:

=============================================

find . -type f | xargs ll | awk '{print $5,$NF}' | while read line ; do
echo $(dirname "$line") $(basename "$line")
done | sort -k 2,2 -k 1n,1 |
awk '{if ($2 != dir) {print"====================";print "Directory - "$2;dir=$2}}{$2="";print}'

=============================================

Rgds, Robin.

[Bill McNAMARA_1]

Sheesh, you're good at the awk stuff Robin!

Nice output...
seems to take a bit of time though, I'd really have prefered an identical or equivalent output a little easier..

Thanks,
Bill

[Santosh Nair_1]

How about modifying the find in my previous posting to:

find . -type f -exec du -sk {} \; |sort -n

Its not sorted in directory order, but it does list all the files and their sizes.

Robin's scripting abilities are amazing...I'm suprised he's not royalty yet.

-Santosh

[Stefan Schulz]

Hi Bill,

hope i understood you right. You want a per directory list of files sorted by size, correct?

I would do something like:

for dir in `ls -d *` do
du -sk $dir/* | sort -rn
done

This will sort the files in each directory descending on filesize.

Hope this helps

Regards Stefan

[Robin Wakefield]

Hi,

Actually, looking at Stefan's solution, mine's a bit OTT, but I've been waiting so long for these pages today, I got a bit carried away.

Rgds, Robin.