mod operator in shell

[andi_1]

Hi,

I have one more quick question:

Suppose, I have to perform the following division:

20/8 = 2.5

What can I use in shell so only 2 is returned?
tmp=20/8
and then tmp==2

Thank you.

[Patrick Wallek · Accepted solution]

Use bc

VAR=`echo "20/8" | bc`
echo $VAR
2

Note that the ` are the backward tic marks.

[Mark Greene_1]

where A=2 and B=5

this will return just 2:
(( C = $B / $A ))

this wil return just the remainder, 1:
(( D = $B % $A ))


HTH
mark